Robert L Pearson vs Charles Lawton
date unknown · Result 0–1 · Zukertort Opening (A04).
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Game details
- White
- Robert L Pearson (1602)
- Black
- Charles Lawton (2117)
- Result
- 0–1
- Opening
- Zukertort Opening (A04)
About this chess game
This chess game between Robert L Pearson (1602) and Charles Lawton (2117) was played and finished 0–1. The opening was the Zukertort Opening (A04). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Robert L Pearson games or Charles Lawton games? This Robert L Pearson vs Charles Lawton encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Robert L Pearson vs Charles Lawton?
Robert L Pearson vs Charles Lawton finished 0–1, a win for Charles Lawton.
What opening was played in Robert L Pearson vs Charles Lawton?
The game opened with the Zukertort Opening (ECO A04).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Robert L Pearson vs Charles Lawton, or open it on the CipherChess analysis board to review it with the Stockfish engine.