Evgenij Piankov vs Marcin Tabola
4. Brno Open 2013, 2013 · Result 1–0 · Nimzo-Indian Defense: Classical Variation, Noa Variation (E36).
Turn this game into your next win
Replay Evgenij Piankov vs Marcin Tabola with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Evgenij Piankov (2264)
- Black
- Marcin Tabola (1990)
- Result
- 1–0
- Event
- 4. Brno Open 2013
- Year
- 2013
- Opening
- Nimzo-Indian Defense: Classical Variation, Noa Variation (E36)
About this chess game
This chess game between Evgenij Piankov (2264) and Marcin Tabola (1990) was played at 4. Brno Open 2013 in 2013 and finished 1–0. The opening was the Nimzo-Indian Defense: Classical Variation, Noa Variation (E36). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Evgenij Piankov games or Marcin Tabola games? This Evgenij Piankov vs Marcin Tabola encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Classical Variation, Noa Variation.
Frequently asked questions
Who won Evgenij Piankov vs Marcin Tabola?
Evgenij Piankov vs Marcin Tabola (2013) finished 1–0, a win for Evgenij Piankov.
What opening was played in Evgenij Piankov vs Marcin Tabola?
The game opened with the Nimzo-Indian Defense: Classical Variation, Noa Variation (ECO E36).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Evgenij Piankov vs Marcin Tabola, or open it on the CipherChess analysis board to review it with the Stockfish engine.