Evgenij Piankov vs Peter Demeter
Tatry Open 2019, 2019 · Result 1–0 · English Opening: Symmetrical Variation, Duchamp Variation (A38).
Turn this game into your next win
Replay Evgenij Piankov vs Peter Demeter with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Evgenij Piankov (2237)
- Black
- Peter Demeter (2117)
- Result
- 1–0
- Event
- Tatry Open 2019
- Year
- 2019
- Opening
- English Opening: Symmetrical Variation, Duchamp Variation (A38)
About this chess game
This chess game between Evgenij Piankov (2237) and Peter Demeter (2117) was played at Tatry Open 2019 in 2019 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Duchamp Variation (A38). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Evgenij Piankov games or Peter Demeter games? This Evgenij Piankov vs Peter Demeter encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Duchamp Variation.
Frequently asked questions
Who won Evgenij Piankov vs Peter Demeter?
Evgenij Piankov vs Peter Demeter (2019) finished 1–0, a win for Evgenij Piankov.
What opening was played in Evgenij Piankov vs Peter Demeter?
The game opened with the English Opening: Symmetrical Variation, Duchamp Variation (ECO A38).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Evgenij Piankov vs Peter Demeter, or open it on the CipherChess analysis board to review it with the Stockfish engine.