Yang-Jian Zhou vs Colin R Ramage
British Week 2 PM, 2014 · Result 0–1 · English Opening: Symmetrical Variation, Normal Variation (A34).
Turn this game into your next win
Replay Yang-Jian Zhou vs Colin R Ramage with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Yang-Jian Zhou (1755)
- Black
- Colin R Ramage (1908)
- Result
- 0–1
- Event
- British Week 2 PM
- Year
- 2014
- Opening
- English Opening: Symmetrical Variation, Normal Variation (A34)
About this chess game
This chess game between Yang-Jian Zhou (1755) and Colin R Ramage (1908) was played at British Week 2 PM in 2014 and finished 0–1. The opening was the English Opening: Symmetrical Variation, Normal Variation (A34). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Yang-Jian Zhou games or Colin R Ramage games? This Yang-Jian Zhou vs Colin R Ramage encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Normal Variation.
Frequently asked questions
Who won Yang-Jian Zhou vs Colin R Ramage?
Yang-Jian Zhou vs Colin R Ramage (2014) finished 0–1, a win for Colin R Ramage.
What opening was played in Yang-Jian Zhou vs Colin R Ramage?
The game opened with the English Opening: Symmetrical Variation, Normal Variation (ECO A34).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Yang-Jian Zhou vs Colin R Ramage, or open it on the CipherChess analysis board to review it with the Stockfish engine.