Alex Yermolinsky vs Mikhail Braude

New York Open, 1992 · Result 0–1 · English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17).

Mikhail Braude24801

Alex Yermolinsky25950

Notation · 96 moves

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Game details

White: Alex Yermolinsky (2595)
Black: Mikhail Braude (2480)
Result: 0–1
Event: New York Open
Year: 1992
Opening: English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17)

About this chess game

This chess game between Alex Yermolinsky (2595) and Mikhail Braude (2480) was played at New York Open in 1992 and finished 0–1. The opening was the English Opening: Anglo-Indian Defense, Queen's Indian Formation (A17). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.

Looking for more Alex Yermolinsky games or Mikhail Braude games? This Alex Yermolinsky vs Mikhail Braude encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Anglo-Indian Defense, Queen's Indian Formation.

Frequently asked questions

Who won Alex Yermolinsky vs Mikhail Braude?

Alex Yermolinsky vs Mikhail Braude (1992) finished 0–1, a win for Mikhail Braude.

What opening was played in Alex Yermolinsky vs Mikhail Braude?

The game opened with the English Opening: Anglo-Indian Defense, Queen's Indian Formation (ECO A17).

Can I replay this chess game move by move?

Yes. Use the interactive board on this page to step through every move of Alex Yermolinsky vs Mikhail Braude, or open it on the CipherChess analysis board to review it with the Stockfish engine.