Alexander A. Yakimenko vs Sofya Pikalova
22. Voronezh FIDE Open, 2018 · Result 1–0 · Sicilian Defense: Closed (B23).
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Game details
- White
- Alexander A. Yakimenko (2094)
- Black
- Sofya Pikalova (1739)
- Result
- 1–0
- Event
- 22. Voronezh FIDE Open
- Year
- 2018
- Opening
- Sicilian Defense: Closed (B23)
About this chess game
This chess game between Alexander A. Yakimenko (2094) and Sofya Pikalova (1739) was played at 22. Voronezh FIDE Open in 2018 and finished 1–0. The opening was the Sicilian Defense: Closed (B23). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander A. Yakimenko games or Sofya Pikalova games? This Alexander A. Yakimenko vs Sofya Pikalova encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Closed.
Frequently asked questions
Who won Alexander A. Yakimenko vs Sofya Pikalova?
Alexander A. Yakimenko vs Sofya Pikalova (2018) finished 1–0, a win for Alexander A. Yakimenko.
What opening was played in Alexander A. Yakimenko vs Sofya Pikalova?
The game opened with the Sicilian Defense: Closed (ECO B23).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander A. Yakimenko vs Sofya Pikalova, or open it on the CipherChess analysis board to review it with the Stockfish engine.