Tom E Wiley vs Alexander Lagunow
Bremen Silvester Open A, 2022 · Result ½–½ · Nimzo-Indian Defense: Classical Variation, Noa Variation (E35).
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Game details
- White
- Tom E Wiley (2125)
- Black
- Alexander Lagunow (2357)
- Result
- ½–½
- Event
- Bremen Silvester Open A
- Year
- 2022
- Opening
- Nimzo-Indian Defense: Classical Variation, Noa Variation (E35)
About this chess game
This chess game between Tom E Wiley (2125) and Alexander Lagunow (2357) was played at Bremen Silvester Open A in 2022 and finished ½–½. The opening was the Nimzo-Indian Defense: Classical Variation, Noa Variation (E35). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Tom E Wiley games or Alexander Lagunow games? This Tom E Wiley vs Alexander Lagunow encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Nimzo-Indian Defense: Classical Variation, Noa Variation.
Frequently asked questions
Who won Tom E Wiley vs Alexander Lagunow?
Tom E Wiley vs Alexander Lagunow (2022) finished ½–½, and the game was drawn.
What opening was played in Tom E Wiley vs Alexander Lagunow?
The game opened with the Nimzo-Indian Defense: Classical Variation, Noa Variation (ECO E35).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Tom E Wiley vs Alexander Lagunow, or open it on the CipherChess analysis board to review it with the Stockfish engine.