Lukas Weissmann vs Martin Cuhra
35. Czech Open E 2024, 2024 · Result 0–1 · English Opening: Symmetrical Variation, Normal Variation (A34).
Turn this game into your next win
Replay Lukas Weissmann vs Martin Cuhra with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Lukas Weissmann (2111)
- Black
- Martin Cuhra (2273)
- Result
- 0–1
- Event
- 35. Czech Open E 2024
- Year
- 2024
- Opening
- English Opening: Symmetrical Variation, Normal Variation (A34)
About this chess game
This chess game between Lukas Weissmann (2111) and Martin Cuhra (2273) was played at 35. Czech Open E 2024 in 2024 and finished 0–1. The opening was the English Opening: Symmetrical Variation, Normal Variation (A34). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Lukas Weissmann games or Martin Cuhra games? This Lukas Weissmann vs Martin Cuhra encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Normal Variation.
Frequently asked questions
Who won Lukas Weissmann vs Martin Cuhra?
Lukas Weissmann vs Martin Cuhra (2024) finished 0–1, a win for Martin Cuhra.
What opening was played in Lukas Weissmann vs Martin Cuhra?
The game opened with the English Opening: Symmetrical Variation, Normal Variation (ECO A34).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Lukas Weissmann vs Martin Cuhra, or open it on the CipherChess analysis board to review it with the Stockfish engine.