John Watson vs Levon Aronian
Ubeda Open 4th, 1999 · Result 0–1 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- John Watson (2357)
- Black
- Levon Aronian (2502)
- Result
- 0–1
- Event
- Ubeda Open 4th
- Year
- 1999
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between John Watson (2357) and Levon Aronian (2502) was played at Ubeda Open 4th in 1999 and finished 0–1. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more John Watson games or Levon Aronian games? This John Watson vs Levon Aronian encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won John Watson vs Levon Aronian?
John Watson vs Levon Aronian (1999) finished 0–1, a win for Levon Aronian.
What opening was played in John Watson vs Levon Aronian?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of John Watson vs Levon Aronian, or open it on the CipherChess analysis board to review it with the Stockfish engine.