Dieter Wallner vs Re Horvath
AUT Ch 2017, 2017 · Result 1–0 · Dutch Defense: Leningrad Variation, Warsaw Variation (A88).
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Game details
- White
- Dieter Wallner (2082)
- Black
- Re Horvath (2039)
- Result
- 1–0
- Event
- AUT Ch 2017
- Year
- 2017
- Opening
- Dutch Defense: Leningrad Variation, Warsaw Variation (A88)
About this chess game
This chess game between Dieter Wallner (2082) and Re Horvath (2039) was played at AUT Ch 2017 in 2017 and finished 1–0. The opening was the Dutch Defense: Leningrad Variation, Warsaw Variation (A88). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Dieter Wallner games or Re Horvath games? This Dieter Wallner vs Re Horvath encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Leningrad Variation, Warsaw Variation.
Frequently asked questions
Who won Dieter Wallner vs Re Horvath?
Dieter Wallner vs Re Horvath (2017) finished 1–0, a win for Dieter Wallner.
What opening was played in Dieter Wallner vs Re Horvath?
The game opened with the Dutch Defense: Leningrad Variation, Warsaw Variation (ECO A88).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Dieter Wallner vs Re Horvath, or open it on the CipherChess analysis board to review it with the Stockfish engine.