John Paul Wallace vs Stephen Muhammad
Australia, 1991 · Result 1–0 · Semi-Slav Defense: Accelerated Meran Variation (D45).
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Game details
- White
- John Paul Wallace (2340)
- Black
- Stephen Muhammad (1997)
- Result
- 1–0
- Event
- Australia
- Year
- 1991
- Opening
- Semi-Slav Defense: Accelerated Meran Variation (D45)
About this chess game
This chess game between John Paul Wallace (2340) and Stephen Muhammad (1997) was played at Australia in 1991 and finished 1–0. The opening was the Semi-Slav Defense: Accelerated Meran Variation (D45). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more John Paul Wallace games or Stephen Muhammad games? This John Paul Wallace vs Stephen Muhammad encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Semi-Slav Defense: Accelerated Meran Variation.
Frequently asked questions
Who won John Paul Wallace vs Stephen Muhammad?
John Paul Wallace vs Stephen Muhammad (1991) finished 1–0, a win for John Paul Wallace.
What opening was played in John Paul Wallace vs Stephen Muhammad?
The game opened with the Semi-Slav Defense: Accelerated Meran Variation (ECO D45).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of John Paul Wallace vs Stephen Muhammad, or open it on the CipherChess analysis board to review it with the Stockfish engine.