Aleksandr Vladimirov vs Alexander Schur
St Petersburg, 1992 · Result 1–0 · King's Indian Defense: Normal Variation (E70).
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Game details
- White
- Aleksandr Vladimirov (2067)
- Black
- Alexander Schur (2011)
- Result
- 1–0
- Event
- St Petersburg
- Year
- 1992
- Opening
- King's Indian Defense: Normal Variation (E70)
About this chess game
This chess game between Aleksandr Vladimirov (2067) and Alexander Schur (2011) was played at St Petersburg in 1992 and finished 1–0. The opening was the King's Indian Defense: Normal Variation (E70). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Aleksandr Vladimirov games or Alexander Schur games? This Aleksandr Vladimirov vs Alexander Schur encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Normal Variation.
Frequently asked questions
Who won Aleksandr Vladimirov vs Alexander Schur?
Aleksandr Vladimirov vs Alexander Schur (1992) finished 1–0, a win for Aleksandr Vladimirov.
What opening was played in Aleksandr Vladimirov vs Alexander Schur?
The game opened with the King's Indian Defense: Normal Variation (ECO E70).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Aleksandr Vladimirov vs Alexander Schur, or open it on the CipherChess analysis board to review it with the Stockfish engine.