Alexandre Letizio Vieira vs Kayo Ribeiro Nachef
2015 · Result 1–0 · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Alexandre Letizio Vieira vs Kayo Ribeiro Nachef with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Alexandre Letizio Vieira (1850)
- Black
- Kayo Ribeiro Nachef (1709)
- Result
- 1–0
- Year
- 2015
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Alexandre Letizio Vieira (1850) and Kayo Ribeiro Nachef (1709) was played in 2015 and finished 1–0. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexandre Letizio Vieira games or Kayo Ribeiro Nachef games? This Alexandre Letizio Vieira vs Kayo Ribeiro Nachef encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Alexandre Letizio Vieira vs Kayo Ribeiro Nachef?
Alexandre Letizio Vieira vs Kayo Ribeiro Nachef (2015) finished 1–0, a win for Alexandre Letizio Vieira.
What opening was played in Alexandre Letizio Vieira vs Kayo Ribeiro Nachef?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexandre Letizio Vieira vs Kayo Ribeiro Nachef, or open it on the CipherChess analysis board to review it with the Stockfish engine.