Rodrigo Vasquez Schroeder vs Tingjie Lei
44. Seville Open 2019, 2019 · Result ½–½ · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Rodrigo Vasquez Schroeder vs Tingjie Lei with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Rodrigo Vasquez Schroeder (2499)
- Black
- Tingjie Lei (2447)
- Result
- ½–½
- Event
- 44. Seville Open 2019
- Year
- 2019
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Rodrigo Vasquez Schroeder (2499) and Tingjie Lei (2447) was played at 44. Seville Open 2019 in 2019 and finished ½–½. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Rodrigo Vasquez Schroeder games or Tingjie Lei games? This Rodrigo Vasquez Schroeder vs Tingjie Lei encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Rodrigo Vasquez Schroeder vs Tingjie Lei?
Rodrigo Vasquez Schroeder vs Tingjie Lei (2019) finished ½–½, and the game was drawn.
What opening was played in Rodrigo Vasquez Schroeder vs Tingjie Lei?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Rodrigo Vasquez Schroeder vs Tingjie Lei, or open it on the CipherChess analysis board to review it with the Stockfish engine.