Jason Vandenberghe vs Nathan De Strycker
2009 · Result 1–0 · French Defense: Classical Variation, Normal Variation (C13).
Turn this game into your next win
Replay Jason Vandenberghe vs Nathan De Strycker with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Jason Vandenberghe (1828)
- Black
- Nathan De Strycker (1738)
- Result
- 1–0
- Year
- 2009
- Opening
- French Defense: Classical Variation, Normal Variation (C13)
About this chess game
This chess game between Jason Vandenberghe (1828) and Nathan De Strycker (1738) was played in 2009 and finished 1–0. The opening was the French Defense: Classical Variation, Normal Variation (C13). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Jason Vandenberghe games or Nathan De Strycker games? This Jason Vandenberghe vs Nathan De Strycker encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the French Defense: Classical Variation, Normal Variation.
Frequently asked questions
Who won Jason Vandenberghe vs Nathan De Strycker?
Jason Vandenberghe vs Nathan De Strycker (2009) finished 1–0, a win for Jason Vandenberghe.
What opening was played in Jason Vandenberghe vs Nathan De Strycker?
The game opened with the French Defense: Classical Variation, Normal Variation (ECO C13).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Jason Vandenberghe vs Nathan De Strycker, or open it on the CipherChess analysis board to review it with the Stockfish engine.