Wessel Van Kessel vs Miaoyi Lu
38. Geraardsbergen Open, 2023 · Result 1–0 · English Opening: Agincourt Defense, Neo-Catalan Declined (A14).
Turn this game into your next win
Replay Wessel Van Kessel vs Miaoyi Lu with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Wessel Van Kessel (2146)
- Black
- Miaoyi Lu (2226)
- Result
- 1–0
- Event
- 38. Geraardsbergen Open
- Year
- 2023
- Opening
- English Opening: Agincourt Defense, Neo-Catalan Declined (A14)
About this chess game
This chess game between Wessel Van Kessel (2146) and Miaoyi Lu (2226) was played at 38. Geraardsbergen Open in 2023 and finished 1–0. The opening was the English Opening: Agincourt Defense, Neo-Catalan Declined (A14). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Wessel Van Kessel games or Miaoyi Lu games? This Wessel Van Kessel vs Miaoyi Lu encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Agincourt Defense, Neo-Catalan Declined.
Frequently asked questions
Who won Wessel Van Kessel vs Miaoyi Lu?
Wessel Van Kessel vs Miaoyi Lu (2023) finished 1–0, a win for Wessel Van Kessel.
What opening was played in Wessel Van Kessel vs Miaoyi Lu?
The game opened with the English Opening: Agincourt Defense, Neo-Catalan Declined (ECO A14).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Wessel Van Kessel vs Miaoyi Lu, or open it on the CipherChess analysis board to review it with the Stockfish engine.