Vladimir Utemov vs Alexander Berelowitsch
Smolensk, 1992 · Result 1–0 · Old Indian Defense (A53).
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Game details
- White
- Vladimir Utemov (2435)
- Black
- Alexander Berelowitsch (2285)
- Result
- 1–0
- Event
- Smolensk
- Year
- 1992
- Opening
- Old Indian Defense (A53)
About this chess game
This chess game between Vladimir Utemov (2435) and Alexander Berelowitsch (2285) was played at Smolensk in 1992 and finished 1–0. The opening was the Old Indian Defense (A53). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Vladimir Utemov games or Alexander Berelowitsch games? This Vladimir Utemov vs Alexander Berelowitsch encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense.
Frequently asked questions
Who won Vladimir Utemov vs Alexander Berelowitsch?
Vladimir Utemov vs Alexander Berelowitsch (1992) finished 1–0, a win for Vladimir Utemov.
What opening was played in Vladimir Utemov vs Alexander Berelowitsch?
The game opened with the Old Indian Defense (ECO A53).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Vladimir Utemov vs Alexander Berelowitsch, or open it on the CipherChess analysis board to review it with the Stockfish engine.