Maxim Turov vs Johnatan Bakalchuk
Budapest Spring Open 2018, 2018 · Result 1–0 · Indian Defense: Przepiorka Variation (A49).
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Game details
- White
- Maxim Turov (2610)
- Black
- Johnatan Bakalchuk (2410)
- Result
- 1–0
- Event
- Budapest Spring Open 2018
- Year
- 2018
- Opening
- Indian Defense: Przepiorka Variation (A49)
About this chess game
This chess game between Maxim Turov (2610) and Johnatan Bakalchuk (2410) was played at Budapest Spring Open 2018 in 2018 and finished 1–0. The opening was the Indian Defense: Przepiorka Variation (A49). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Maxim Turov games or Johnatan Bakalchuk games? This Maxim Turov vs Johnatan Bakalchuk encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Przepiorka Variation.
Frequently asked questions
Who won Maxim Turov vs Johnatan Bakalchuk?
Maxim Turov vs Johnatan Bakalchuk (2018) finished 1–0, a win for Maxim Turov.
What opening was played in Maxim Turov vs Johnatan Bakalchuk?
The game opened with the Indian Defense: Przepiorka Variation (ECO A49).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Maxim Turov vs Johnatan Bakalchuk, or open it on the CipherChess analysis board to review it with the Stockfish engine.