Joan Torres Teruel vs Fernando Poyato Ruiz
2019 · Result 0–1 · Hungarian Opening: Wiedenhagen-Beta Gambit (A07).
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Game details
- White
- Joan Torres Teruel (1455)
- Black
- Fernando Poyato Ruiz (1890)
- Result
- 0–1
- Year
- 2019
- Opening
- Hungarian Opening: Wiedenhagen-Beta Gambit (A07)
About this chess game
This chess game between Joan Torres Teruel (1455) and Fernando Poyato Ruiz (1890) was played in 2019 and finished 0–1. The opening was the Hungarian Opening: Wiedenhagen-Beta Gambit (A07). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Joan Torres Teruel games or Fernando Poyato Ruiz games? This Joan Torres Teruel vs Fernando Poyato Ruiz encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Hungarian Opening: Wiedenhagen-Beta Gambit.
Frequently asked questions
Who won Joan Torres Teruel vs Fernando Poyato Ruiz?
Joan Torres Teruel vs Fernando Poyato Ruiz (2019) finished 0–1, a win for Fernando Poyato Ruiz.
What opening was played in Joan Torres Teruel vs Fernando Poyato Ruiz?
The game opened with the Hungarian Opening: Wiedenhagen-Beta Gambit (ECO A07).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Joan Torres Teruel vs Fernando Poyato Ruiz, or open it on the CipherChess analysis board to review it with the Stockfish engine.