Ana Topuridze vs Harout Simonian
BCSA Open, 2003 · Result 0–1 · Old Indian Defense: Normal Variation (A55).
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Game details
- White
- Ana Topuridze (2122)
- Black
- Harout Simonian (2270)
- Result
- 0–1
- Event
- BCSA Open
- Year
- 2003
- Opening
- Old Indian Defense: Normal Variation (A55)
About this chess game
This chess game between Ana Topuridze (2122) and Harout Simonian (2270) was played at BCSA Open in 2003 and finished 0–1. The opening was the Old Indian Defense: Normal Variation (A55). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Ana Topuridze games or Harout Simonian games? This Ana Topuridze vs Harout Simonian encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Old Indian Defense: Normal Variation.
Frequently asked questions
Who won Ana Topuridze vs Harout Simonian?
Ana Topuridze vs Harout Simonian (2003) finished 0–1, a win for Harout Simonian.
What opening was played in Ana Topuridze vs Harout Simonian?
The game opened with the Old Indian Defense: Normal Variation (ECO A55).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Ana Topuridze vs Harout Simonian, or open it on the CipherChess analysis board to review it with the Stockfish engine.