Alexander Iordanov Todorov vs Vlatko Marendic
1992 · Result 0–1 · Indian Defense (A45).
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Game details
- Black
- Vlatko Marendic (2195)
- Result
- 0–1
- Year
- 1992
- Opening
- Indian Defense (A45)
About this chess game
This chess game between Alexander Iordanov Todorov and Vlatko Marendic (2195) was played in 1992 and finished 0–1. The opening was the Indian Defense (A45). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Iordanov Todorov games or Vlatko Marendic games? This Alexander Iordanov Todorov vs Vlatko Marendic encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense.
Frequently asked questions
Who won Alexander Iordanov Todorov vs Vlatko Marendic?
Alexander Iordanov Todorov vs Vlatko Marendic (1992) finished 0–1, a win for Vlatko Marendic.
What opening was played in Alexander Iordanov Todorov vs Vlatko Marendic?
The game opened with the Indian Defense (ECO A45).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Iordanov Todorov vs Vlatko Marendic, or open it on the CipherChess analysis board to review it with the Stockfish engine.