Aleksandr Titov vs Alexander Shabalov
Minsk, 1986 · Result 1–0 · East Indian Defense (A48).
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Game details
- White
- Aleksandr Titov
- Black
- Alexander Shabalov (2365)
- Result
- 1–0
- Event
- Minsk
- Year
- 1986
- Opening
- East Indian Defense (A48)
About this chess game
This chess game between Aleksandr Titov and Alexander Shabalov (2365) was played at Minsk in 1986 and finished 1–0. The opening was the East Indian Defense (A48). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Aleksandr Titov games or Alexander Shabalov games? This Aleksandr Titov vs Alexander Shabalov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the East Indian Defense.
Frequently asked questions
Who won Aleksandr Titov vs Alexander Shabalov?
Aleksandr Titov vs Alexander Shabalov (1986) finished 1–0, a win for Aleksandr Titov.
What opening was played in Aleksandr Titov vs Alexander Shabalov?
The game opened with the East Indian Defense (ECO A48).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Aleksandr Titov vs Alexander Shabalov, or open it on the CipherChess analysis board to review it with the Stockfish engine.