Eu Wen Aron Teh vs Stefan Marinescu
2013 · Result 1–0 · King's Indian Defense: Normal Variation, Standard Development (E73).
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Game details
- White
- Eu Wen Aron Teh (1949)
- Black
- Stefan Marinescu (1967)
- Result
- 1–0
- Year
- 2013
- Opening
- King's Indian Defense: Normal Variation, Standard Development (E73)
About this chess game
This chess game between Eu Wen Aron Teh (1949) and Stefan Marinescu (1967) was played in 2013 and finished 1–0. The opening was the King's Indian Defense: Normal Variation, Standard Development (E73). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Eu Wen Aron Teh games or Stefan Marinescu games? This Eu Wen Aron Teh vs Stefan Marinescu encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Normal Variation, Standard Development.
Frequently asked questions
Who won Eu Wen Aron Teh vs Stefan Marinescu?
Eu Wen Aron Teh vs Stefan Marinescu (2013) finished 1–0, a win for Eu Wen Aron Teh.
What opening was played in Eu Wen Aron Teh vs Stefan Marinescu?
The game opened with the King's Indian Defense: Normal Variation, Standard Development (ECO E73).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Eu Wen Aron Teh vs Stefan Marinescu, or open it on the CipherChess analysis board to review it with the Stockfish engine.