Antoni Szustakowski vs Bogdan Lalic
30. Czech Open A 2019, 2019 · Result 0–1 · Queen's Indian Defense: Yates Variation (E16).
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Game details
- White
- Antoni Szustakowski (2279)
- Black
- Bogdan Lalic (2411)
- Result
- 0–1
- Event
- 30. Czech Open A 2019
- Year
- 2019
- Opening
- Queen's Indian Defense: Yates Variation (E16)
About this chess game
This chess game between Antoni Szustakowski (2279) and Bogdan Lalic (2411) was played at 30. Czech Open A 2019 in 2019 and finished 0–1. The opening was the Queen's Indian Defense: Yates Variation (E16). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Antoni Szustakowski games or Bogdan Lalic games? This Antoni Szustakowski vs Bogdan Lalic encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Indian Defense: Yates Variation.
Frequently asked questions
Who won Antoni Szustakowski vs Bogdan Lalic?
Antoni Szustakowski vs Bogdan Lalic (2019) finished 0–1, a win for Bogdan Lalic.
What opening was played in Antoni Szustakowski vs Bogdan Lalic?
The game opened with the Queen's Indian Defense: Yates Variation (ECO E16).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Antoni Szustakowski vs Bogdan Lalic, or open it on the CipherChess analysis board to review it with the Stockfish engine.