Stephen Swanson vs Jake Z Liang
London Classic Rapid Open, 2017 · Result 1–0 · Zukertort Opening (A04).
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Game details
- White
- Stephen Swanson (2190)
- Black
- Jake Z Liang (2046)
- Result
- 1–0
- Event
- London Classic Rapid Open
- Year
- 2017
- Opening
- Zukertort Opening (A04)
About this chess game
This chess game between Stephen Swanson (2190) and Jake Z Liang (2046) was played at London Classic Rapid Open in 2017 and finished 1–0. The opening was the Zukertort Opening (A04). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Stephen Swanson games or Jake Z Liang games? This Stephen Swanson vs Jake Z Liang encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Stephen Swanson vs Jake Z Liang?
Stephen Swanson vs Jake Z Liang (2017) finished 1–0, a win for Stephen Swanson.
What opening was played in Stephen Swanson vs Jake Z Liang?
The game opened with the Zukertort Opening (ECO A04).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Stephen Swanson vs Jake Z Liang, or open it on the CipherChess analysis board to review it with the Stockfish engine.