Frantisek Stross vs Petr Neuman
21. Klatovy Open 2015, 2015 · Result ½–½ · Sicilian Defense: Najdorf Variation, Amsterdam Variation (B93).
Turn this game into your next win
Replay Frantisek Stross vs Petr Neuman with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Frantisek Stross (2326)
- Black
- Petr Neuman (2470)
- Result
- ½–½
- Event
- 21. Klatovy Open 2015
- Year
- 2015
- Opening
- Sicilian Defense: Najdorf Variation, Amsterdam Variation (B93)
About this chess game
This chess game between Frantisek Stross (2326) and Petr Neuman (2470) was played at 21. Klatovy Open 2015 in 2015 and finished ½–½. The opening was the Sicilian Defense: Najdorf Variation, Amsterdam Variation (B93). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Frantisek Stross games or Petr Neuman games? This Frantisek Stross vs Petr Neuman encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Najdorf Variation, Amsterdam Variation.
Frequently asked questions
Who won Frantisek Stross vs Petr Neuman?
Frantisek Stross vs Petr Neuman (2015) finished ½–½, and the game was drawn.
What opening was played in Frantisek Stross vs Petr Neuman?
The game opened with the Sicilian Defense: Najdorf Variation, Amsterdam Variation (ECO B93).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Frantisek Stross vs Petr Neuman, or open it on the CipherChess analysis board to review it with the Stockfish engine.