Jan Stoop vs Lidia Zdziarska-Zareba
2013 · Result 0–1 · English Opening: Symmetrical Variation, Four Knights Variation (A35).
Turn this game into your next win
Replay Jan Stoop vs Lidia Zdziarska-Zareba with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Jan Stoop (1782)
- Black
- Lidia Zdziarska-Zareba (1942)
- Result
- 0–1
- Year
- 2013
- Opening
- English Opening: Symmetrical Variation, Four Knights Variation (A35)
About this chess game
This chess game between Jan Stoop (1782) and Lidia Zdziarska-Zareba (1942) was played in 2013 and finished 0–1. The opening was the English Opening: Symmetrical Variation, Four Knights Variation (A35). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Jan Stoop games or Lidia Zdziarska-Zareba games? This Jan Stoop vs Lidia Zdziarska-Zareba encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Four Knights Variation.
Frequently asked questions
Who won Jan Stoop vs Lidia Zdziarska-Zareba?
Jan Stoop vs Lidia Zdziarska-Zareba (2013) finished 0–1, a win for Lidia Zdziarska-Zareba.
What opening was played in Jan Stoop vs Lidia Zdziarska-Zareba?
The game opened with the English Opening: Symmetrical Variation, Four Knights Variation (ECO A35).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Jan Stoop vs Lidia Zdziarska-Zareba, or open it on the CipherChess analysis board to review it with the Stockfish engine.