Chess Game
Florian Staub vs Marc Berreth
2000 · Result 1–0 · Old Indian Defense: Normal Variation (A55).
Marc Berreth0
Florian Staub1
Notation · 85 moves
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1. c4 Nf6 2. Nc3 c6 3. e4 e5 4. Nf3 d6 5. d4 Nbd7 6. Bg5 Qa5 7. Bd2 Qb6 8. c5 dxc5 9. dxe5 Ng4 10. e6 fxe6 11. Bc4 Nde5 12. Nxe5 Nxe5 13. Qh5+ Ng6 14. f4 Qd8 15. g3 Qd4 16. Bb3 Bd7 17. O-O-O O-O-O 18. e5 Ne7 19. Ne2 Qe4 20. Bc2 Qc4 21. Kb1 Be8 22. Qf3 Bg6 23. Bxg6 Nxg6 24. Ba5 Rxd1+ 25. Rxd1 Be7 26. Nc1 Bd8 27. Bc3 Ne7 28. b3 Qb5 29. g4 Nd5 30. Bb2 Rf8 31. f5 c4 32. bxc4 Qxc4 33. Nb3 Bg5 34. Rd4 Qb5 35. Ba3 Rf7 36. h3 Ne3 37. h4 c5 38. Bxc5 Bh6 39. g5 Rc7 40. Qxe3 Rxc5 41. Rd1 Bxg5 42. hxg5 Rxe5 43. Qc3+ 1–0
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About this game
This chess game between Florian Staub (1980) and Marc Berreth (2107) was played in 2000 and finished 1–0. The opening was the Old Indian Defense: Normal Variation (A55). Step through every move on the interactive board above, or open it on the CipherChess board to analyse the game with the engine. You can also explore more games by Florian Staub and Marc Berreth from the CipherChess mega database.