Chess Game
Valentin V Statsenko vs Aleksandr Bobin
3. Open, 1999 · Result 1–0 · Zukertort Opening (A04).
Aleksandr Bobin0
Valentin V Statsenko1
Notation · 91 moves
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1. Nf3 d6 2. g3 g6 3. c4 e5 4. Nc3 f5 5. d3 Nf6 6. Bg2 Bg7 7. Qb3 c5 8. Bg5 O-O 9. Nd5 Nc6 10. O-O Rb8 11. e3 Be6 12. Nd2 Ne7 13. Bxf6 Bxf6 14. Nxf6+ Rxf6 15. Qc3 Qc7 16. f4 Rf7 17. fxe5 d5 18. Nf3 h6 19. b3 g5 20. Rac1 b6 21. d4 Rc8 22. Nd2 Qd7 23. Qb2 Rd8 24. Rfd1 Nc6 25. cxd5 Bxd5 26. Nc4 Bxg2 27. Qxg2 cxd4 28. Nd6 Nxe5 29. Nxf7 Qxf7 30. exd4 Ng4 31. Qe2 Kg7 32. d5 Nf6 33. d6 Ne4 34. Rc7 Rd7 35. Qb2+ Kg6 36. Qe5 Nf6 37. Rdc1 Ne8 38. R7c6 Kh5 39. Rc8 Ng7 40. Rh8 Ne6 41. Rcc8 f4 42. Rce8 Nc5 43. Reg8 Ne6 44. h3 Ng7 45. g4+ Kh4 46. Kh2 1–0
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About this game
This chess game between Valentin V Statsenko (2045) and Aleksandr Bobin (2274) was played at 3. Open in 1999 and finished 1–0. The opening was the Zukertort Opening (A04). Step through every move on the interactive board above, or open it on the CipherChess board to analyse the game with the engine. You can also explore more games by Valentin V Statsenko and Aleksandr Bobin from the CipherChess mega database.