Alexander Stanishevsky vs Tatyana Neporozhnjaya
Maestro Open, 2008 · Result 0–1 · Ruy Lopez: Closed, Averbakh Variation (C87).
Turn this game into your next win
Replay Alexander Stanishevsky vs Tatyana Neporozhnjaya with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Alexander Stanishevsky (1972)
- Result
- 0–1
- Event
- Maestro Open
- Year
- 2008
- Opening
- Ruy Lopez: Closed, Averbakh Variation (C87)
About this chess game
This chess game between Alexander Stanishevsky (1972) and Tatyana Neporozhnjaya was played at Maestro Open in 2008 and finished 0–1. The opening was the Ruy Lopez: Closed, Averbakh Variation (C87). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Stanishevsky games or Tatyana Neporozhnjaya games? This Alexander Stanishevsky vs Tatyana Neporozhnjaya encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Ruy Lopez: Closed, Averbakh Variation.
Frequently asked questions
Who won Alexander Stanishevsky vs Tatyana Neporozhnjaya?
Alexander Stanishevsky vs Tatyana Neporozhnjaya (2008) finished 0–1, a win for Tatyana Neporozhnjaya.
What opening was played in Alexander Stanishevsky vs Tatyana Neporozhnjaya?
The game opened with the Ruy Lopez: Closed, Averbakh Variation (ECO C87).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Stanishevsky vs Tatyana Neporozhnjaya, or open it on the CipherChess analysis board to review it with the Stockfish engine.