Miguel Angel Soto vs Oscar Marino Agudelo Pineres
2017 · Result 1–0 · Sicilian Defense: Najdorf Variation (B90).
Turn this game into your next win
Replay Miguel Angel Soto vs Oscar Marino Agudelo Pineres with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Miguel Angel Soto (2316)
- Black
- Oscar Marino Agudelo Pineres (2030)
- Result
- 1–0
- Year
- 2017
- Opening
- Sicilian Defense: Najdorf Variation (B90)
About this chess game
This chess game between Miguel Angel Soto (2316) and Oscar Marino Agudelo Pineres (2030) was played in 2017 and finished 1–0. The opening was the Sicilian Defense: Najdorf Variation (B90). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Miguel Angel Soto games or Oscar Marino Agudelo Pineres games? This Miguel Angel Soto vs Oscar Marino Agudelo Pineres encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Najdorf Variation.
Frequently asked questions
Who won Miguel Angel Soto vs Oscar Marino Agudelo Pineres?
Miguel Angel Soto vs Oscar Marino Agudelo Pineres (2017) finished 1–0, a win for Miguel Angel Soto.
What opening was played in Miguel Angel Soto vs Oscar Marino Agudelo Pineres?
The game opened with the Sicilian Defense: Najdorf Variation (ECO B90).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Miguel Angel Soto vs Oscar Marino Agudelo Pineres, or open it on the CipherChess analysis board to review it with the Stockfish engine.