Bogdan Sliwa vs Alexander V Tolush
Riga, 1959 · Result 0–1 · Dutch Defense: Classical Variation (A91).
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Game details
- White
- Bogdan Sliwa
- Black
- Alexander V Tolush
- Result
- 0–1
- Event
- Riga
- Year
- 1959
- Opening
- Dutch Defense: Classical Variation (A91)
About this chess game
This chess game between Bogdan Sliwa and Alexander V Tolush was played at Riga in 1959 and finished 0–1. The opening was the Dutch Defense: Classical Variation (A91). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bogdan Sliwa games or Alexander V Tolush games? This Bogdan Sliwa vs Alexander V Tolush encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Dutch Defense: Classical Variation.
Frequently asked questions
Who won Bogdan Sliwa vs Alexander V Tolush?
Bogdan Sliwa vs Alexander V Tolush (1959) finished 0–1, a win for Alexander V Tolush.
What opening was played in Bogdan Sliwa vs Alexander V Tolush?
The game opened with the Dutch Defense: Classical Variation (ECO A91).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bogdan Sliwa vs Alexander V Tolush, or open it on the CipherChess analysis board to review it with the Stockfish engine.