Andreas Skotheim vs Evgeny E. Vorobiov
Fagernes GM Open 2019, 2019 · Result 0–1 · English Opening: King's English Variation (A20).
Turn this game into your next win
Replay Andreas Skotheim vs Evgeny E. Vorobiov with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Andreas Skotheim (2182)
- Black
- Evgeny E. Vorobiov (2565)
- Result
- 0–1
- Event
- Fagernes GM Open 2019
- Year
- 2019
- Opening
- English Opening: King's English Variation (A20)
About this chess game
This chess game between Andreas Skotheim (2182) and Evgeny E. Vorobiov (2565) was played at Fagernes GM Open 2019 in 2019 and finished 0–1. The opening was the English Opening: King's English Variation (A20). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Andreas Skotheim games or Evgeny E. Vorobiov games? This Andreas Skotheim vs Evgeny E. Vorobiov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: King's English Variation.
Frequently asked questions
Who won Andreas Skotheim vs Evgeny E. Vorobiov?
Andreas Skotheim vs Evgeny E. Vorobiov (2019) finished 0–1, a win for Evgeny E. Vorobiov.
What opening was played in Andreas Skotheim vs Evgeny E. Vorobiov?
The game opened with the English Opening: King's English Variation (ECO A20).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Andreas Skotheim vs Evgeny E. Vorobiov, or open it on the CipherChess analysis board to review it with the Stockfish engine.