Alexander Shemeakin vs Danil Tutov
date unknown · Result 1–0 · King's Indian Defense: Normal Variation (E70).
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Game details
- White
- Alexander Shemeakin (2240)
- Black
- Danil Tutov (1759)
- Result
- 1–0
- Opening
- King's Indian Defense: Normal Variation (E70)
About this chess game
This chess game between Alexander Shemeakin (2240) and Danil Tutov (1759) was played and finished 1–0. The opening was the King's Indian Defense: Normal Variation (E70). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Shemeakin games or Danil Tutov games? This Alexander Shemeakin vs Danil Tutov encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the King's Indian Defense: Normal Variation.
Frequently asked questions
Who won Alexander Shemeakin vs Danil Tutov?
Alexander Shemeakin vs Danil Tutov finished 1–0, a win for Alexander Shemeakin.
What opening was played in Alexander Shemeakin vs Danil Tutov?
The game opened with the King's Indian Defense: Normal Variation (ECO E70).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Shemeakin vs Danil Tutov, or open it on the CipherChess analysis board to review it with the Stockfish engine.