Di Sharma vs Maxim Lugovskoy
17. Delhi Open 2019, 2019 · Result 1–0 · French Defense: Winawer Variation, Advance Variation (C18).
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Game details
- White
- Di Sharma (2303)
- Black
- Maxim Lugovskoy (2445)
- Result
- 1–0
- Event
- 17. Delhi Open 2019
- Year
- 2019
- Opening
- French Defense: Winawer Variation, Advance Variation (C18)
About this chess game
This chess game between Di Sharma (2303) and Maxim Lugovskoy (2445) was played at 17. Delhi Open 2019 in 2019 and finished 1–0. The opening was the French Defense: Winawer Variation, Advance Variation (C18). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Di Sharma games or Maxim Lugovskoy games? This Di Sharma vs Maxim Lugovskoy encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the French Defense: Winawer Variation, Advance Variation.
Frequently asked questions
Who won Di Sharma vs Maxim Lugovskoy?
Di Sharma vs Maxim Lugovskoy (2019) finished 1–0, a win for Di Sharma.
What opening was played in Di Sharma vs Maxim Lugovskoy?
The game opened with the French Defense: Winawer Variation, Advance Variation (ECO C18).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Di Sharma vs Maxim Lugovskoy, or open it on the CipherChess analysis board to review it with the Stockfish engine.