Miguel Santos Ruiz vs Jorden Van Foreest
Budva MNE, 23. EYCC Boys U14, 2013 · Result ½–½ · Sicilian Defense: Alapin Variation (B22).
Turn this game into your next win
Replay Miguel Santos Ruiz vs Jorden Van Foreest with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Miguel Santos Ruiz (2295)
- Black
- Jorden Van Foreest (2310)
- Result
- ½–½
- Event
- Budva MNE, 23. EYCC Boys U14
- Year
- 2013
- Opening
- Sicilian Defense: Alapin Variation (B22)
About this chess game
This chess game between Miguel Santos Ruiz (2295) and Jorden Van Foreest (2310) was played at Budva MNE, 23. EYCC Boys U14 in 2013 and finished ½–½. The opening was the Sicilian Defense: Alapin Variation (B22). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Miguel Santos Ruiz games or Jorden Van Foreest games? This Miguel Santos Ruiz vs Jorden Van Foreest encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Sicilian Defense: Alapin Variation.
Frequently asked questions
Who won Miguel Santos Ruiz vs Jorden Van Foreest?
Miguel Santos Ruiz vs Jorden Van Foreest (2013) finished ½–½, and the game was drawn.
What opening was played in Miguel Santos Ruiz vs Jorden Van Foreest?
The game opened with the Sicilian Defense: Alapin Variation (ECO B22).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Miguel Santos Ruiz vs Jorden Van Foreest, or open it on the CipherChess analysis board to review it with the Stockfish engine.