Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes
2012 · Result ½–½ · Indian Defense: Budapest Defense (A52).
Turn this game into your next win
Replay Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Javier Santana Montjoy (1729)
- Black
- Miguel Angel Arnaiz Yanes (1994)
- Result
- ½–½
- Year
- 2012
- Opening
- Indian Defense: Budapest Defense (A52)
About this chess game
This chess game between Javier Santana Montjoy (1729) and Miguel Angel Arnaiz Yanes (1994) was played in 2012 and finished ½–½. The opening was the Indian Defense: Budapest Defense (A52). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Javier Santana Montjoy games or Miguel Angel Arnaiz Yanes games? This Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.
Frequently asked questions
Who won Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes?
Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes (2012) finished ½–½, and the game was drawn.
What opening was played in Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes?
The game opened with the Indian Defense: Budapest Defense (ECO A52).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Javier Santana Montjoy vs Miguel Angel Arnaiz Yanes, or open it on the CipherChess analysis board to review it with the Stockfish engine.