Bela Sandor vs Arpad Vajda
Budapest, 1950 · Result 1–0 · Queen's Indian Defense: Yates Variation (E16).
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Game details
- White
- Bela Sandor
- Black
- Arpad Vajda
- Result
- 1–0
- Event
- Budapest
- Year
- 1950
- Opening
- Queen's Indian Defense: Yates Variation (E16)
About this chess game
This chess game between Bela Sandor and Arpad Vajda was played at Budapest in 1950 and finished 1–0. The opening was the Queen's Indian Defense: Yates Variation (E16). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bela Sandor games or Arpad Vajda games? This Bela Sandor vs Arpad Vajda encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Indian Defense: Yates Variation.
Frequently asked questions
Who won Bela Sandor vs Arpad Vajda?
Bela Sandor vs Arpad Vajda (1950) finished 1–0, a win for Bela Sandor.
What opening was played in Bela Sandor vs Arpad Vajda?
The game opened with the Queen's Indian Defense: Yates Variation (ECO E16).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bela Sandor vs Arpad Vajda, or open it on the CipherChess analysis board to review it with the Stockfish engine.