Romuald Samisch vs Alexander Popow
Bad Wiessee (28.11.-06.12), 1998 · Result 1–0 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- Romuald Samisch (1907)
- Black
- Alexander Popow (2156)
- Result
- 1–0
- Event
- Bad Wiessee (28.11.-06.12)
- Year
- 1998
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Romuald Samisch (1907) and Alexander Popow (2156) was played at Bad Wiessee (28.11.-06.12) in 1998 and finished 1–0. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Romuald Samisch games or Alexander Popow games? This Romuald Samisch vs Alexander Popow encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Romuald Samisch vs Alexander Popow?
Romuald Samisch vs Alexander Popow (1998) finished 1–0, a win for Romuald Samisch.
What opening was played in Romuald Samisch vs Alexander Popow?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Romuald Samisch vs Alexander Popow, or open it on the CipherChess analysis board to review it with the Stockfish engine.