Francisco Rene Ruiz Gonzales vs Rommel Velasquez
2019 · Result ½–½ · Queen's Pawn Game: Zukertort Variation (D02).
Turn this game into your next win
Replay Francisco Rene Ruiz Gonzales vs Rommel Velasquez with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Francisco Rene Ruiz Gonzales (1667)
- Black
- Rommel Velasquez (2039)
- Result
- ½–½
- Year
- 2019
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Francisco Rene Ruiz Gonzales (1667) and Rommel Velasquez (2039) was played in 2019 and finished ½–½. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Francisco Rene Ruiz Gonzales games or Rommel Velasquez games? This Francisco Rene Ruiz Gonzales vs Rommel Velasquez encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Francisco Rene Ruiz Gonzales vs Rommel Velasquez?
Francisco Rene Ruiz Gonzales vs Rommel Velasquez (2019) finished ½–½, and the game was drawn.
What opening was played in Francisco Rene Ruiz Gonzales vs Rommel Velasquez?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Francisco Rene Ruiz Gonzales vs Rommel Velasquez, or open it on the CipherChess analysis board to review it with the Stockfish engine.