Alexander Rueger vs Tornalf Lehmann
2016 · Result 1–0 · Indian Defense: Budapest Defense (A52).
Turn this game into your next win
Replay Alexander Rueger vs Tornalf Lehmann with deep analysis, save the moments that matter, fold the ideas into your own opening repertoire, and drill the positions until they're second nature. CipherChess turns the games you study into the results you get — free to start.
Start Free on CipherChessMore Games By These Players
Game details
- White
- Alexander Rueger (1840)
- Black
- Tornalf Lehmann (1675)
- Result
- 1–0
- Year
- 2016
- Opening
- Indian Defense: Budapest Defense (A52)
About this chess game
This chess game between Alexander Rueger (1840) and Tornalf Lehmann (1675) was played in 2016 and finished 1–0. The opening was the Indian Defense: Budapest Defense (A52). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alexander Rueger games or Tornalf Lehmann games? This Alexander Rueger vs Tornalf Lehmann encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Budapest Defense.
Frequently asked questions
Who won Alexander Rueger vs Tornalf Lehmann?
Alexander Rueger vs Tornalf Lehmann (2016) finished 1–0, a win for Alexander Rueger.
What opening was played in Alexander Rueger vs Tornalf Lehmann?
The game opened with the Indian Defense: Budapest Defense (ECO A52).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alexander Rueger vs Tornalf Lehmann, or open it on the CipherChess analysis board to review it with the Stockfish engine.