Maxim Rudometov vs Vladimir Liang
Perm RUS, Open June 09, 2009 · Result 0–1 · Zukertort Opening (A04).
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Game details
- White
- Maxim Rudometov (1980)
- Black
- Vladimir Liang (2071)
- Result
- 0–1
- Event
- Perm RUS, Open June 09
- Year
- 2009
- Opening
- Zukertort Opening (A04)
About this chess game
This chess game between Maxim Rudometov (1980) and Vladimir Liang (2071) was played at Perm RUS, Open June 09 in 2009 and finished 0–1. The opening was the Zukertort Opening (A04). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Maxim Rudometov games or Vladimir Liang games? This Maxim Rudometov vs Vladimir Liang encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won Maxim Rudometov vs Vladimir Liang?
Maxim Rudometov vs Vladimir Liang (2009) finished 0–1, a win for Vladimir Liang.
What opening was played in Maxim Rudometov vs Vladimir Liang?
The game opened with the Zukertort Opening (ECO A04).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Maxim Rudometov vs Vladimir Liang, or open it on the CipherChess analysis board to review it with the Stockfish engine.