AM. Rogerson vs Roger D De Coverly
Hereford, 1990 · Result 0–1 · Indian Defense (A45).
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Game details
- White
- AM. Rogerson
- Black
- Roger D De Coverly (2130)
- Result
- 0–1
- Event
- Hereford
- Year
- 1990
- Opening
- Indian Defense (A45)
About this chess game
This chess game between AM. Rogerson and Roger D De Coverly (2130) was played at Hereford in 1990 and finished 0–1. The opening was the Indian Defense (A45). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more AM. Rogerson games or Roger D De Coverly games? This AM. Rogerson vs Roger D De Coverly encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense.
Frequently asked questions
Who won AM. Rogerson vs Roger D De Coverly?
AM. Rogerson vs Roger D De Coverly (1990) finished 0–1, a win for Roger D De Coverly.
What opening was played in AM. Rogerson vs Roger D De Coverly?
The game opened with the Indian Defense (ECO A45).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of AM. Rogerson vs Roger D De Coverly, or open it on the CipherChess analysis board to review it with the Stockfish engine.