Stuart Robertson vs Stephen J Gregory
4NCL Division 2a, 2014 · Result 1–0 · Indian Defense: Normal Variation (A50).
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Game details
- White
- Stuart Robertson (2059)
- Black
- Stephen J Gregory (2083)
- Result
- 1–0
- Event
- 4NCL Division 2a
- Year
- 2014
- Opening
- Indian Defense: Normal Variation (A50)
About this chess game
This chess game between Stuart Robertson (2059) and Stephen J Gregory (2083) was played at 4NCL Division 2a in 2014 and finished 1–0. The opening was the Indian Defense: Normal Variation (A50). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Stuart Robertson games or Stephen J Gregory games? This Stuart Robertson vs Stephen J Gregory encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: Normal Variation.
Frequently asked questions
Who won Stuart Robertson vs Stephen J Gregory?
Stuart Robertson vs Stephen J Gregory (2014) finished 1–0, a win for Stuart Robertson.
What opening was played in Stuart Robertson vs Stephen J Gregory?
The game opened with the Indian Defense: Normal Variation (ECO A50).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Stuart Robertson vs Stephen J Gregory, or open it on the CipherChess analysis board to review it with the Stockfish engine.