J Stuart Robertson vs Bao Nghia Dong
4NCL Division One, 2023 · Result 0–1 · Indian Defense: West Indian Defense (E60).
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Game details
- White
- J Stuart Robertson (2154)
- Black
- Bao Nghia Dong (2359)
- Result
- 0–1
- Event
- 4NCL Division One
- Year
- 2023
- Opening
- Indian Defense: West Indian Defense (E60)
About this chess game
This chess game between J Stuart Robertson (2154) and Bao Nghia Dong (2359) was played at 4NCL Division One in 2023 and finished 0–1. The opening was the Indian Defense: West Indian Defense (E60). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more J Stuart Robertson games or Bao Nghia Dong games? This J Stuart Robertson vs Bao Nghia Dong encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Indian Defense: West Indian Defense.
Frequently asked questions
Who won J Stuart Robertson vs Bao Nghia Dong?
J Stuart Robertson vs Bao Nghia Dong (2023) finished 0–1, a win for Bao Nghia Dong.
What opening was played in J Stuart Robertson vs Bao Nghia Dong?
The game opened with the Indian Defense: West Indian Defense (ECO E60).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of J Stuart Robertson vs Bao Nghia Dong, or open it on the CipherChess analysis board to review it with the Stockfish engine.