F. Robbins vs Dmitr Leykekhman
Detroit Motor City Open, 1994 · Result 0–1 · Zukertort Opening (A05).
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Game details
- White
- F. Robbins
- Black
- Dmitr Leykekhman (2325)
- Result
- 0–1
- Event
- Detroit Motor City Open
- Year
- 1994
- Opening
- Zukertort Opening (A05)
About this chess game
This chess game between F. Robbins and Dmitr Leykekhman (2325) was played at Detroit Motor City Open in 1994 and finished 0–1. The opening was the Zukertort Opening (A05). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more F. Robbins games or Dmitr Leykekhman games? This F. Robbins vs Dmitr Leykekhman encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Zukertort Opening.
Frequently asked questions
Who won F. Robbins vs Dmitr Leykekhman?
F. Robbins vs Dmitr Leykekhman (1994) finished 0–1, a win for Dmitr Leykekhman.
What opening was played in F. Robbins vs Dmitr Leykekhman?
The game opened with the Zukertort Opening (ECO A05).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of F. Robbins vs Dmitr Leykekhman, or open it on the CipherChess analysis board to review it with the Stockfish engine.