Bruce Rind vs David Arnett
Philadelphia, 1992 · Result 1–0 · Slav Defense: Exchange Variation, Symmetrical Line (D14).
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Game details
- White
- Bruce Rind (2375)
- Black
- David Arnett (2335)
- Result
- 1–0
- Event
- Philadelphia
- Year
- 1992
- Opening
- Slav Defense: Exchange Variation, Symmetrical Line (D14)
About this chess game
This chess game between Bruce Rind (2375) and David Arnett (2335) was played at Philadelphia in 1992 and finished 1–0. The opening was the Slav Defense: Exchange Variation, Symmetrical Line (D14). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Bruce Rind games or David Arnett games? This Bruce Rind vs David Arnett encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Slav Defense: Exchange Variation, Symmetrical Line.
Frequently asked questions
Who won Bruce Rind vs David Arnett?
Bruce Rind vs David Arnett (1992) finished 1–0, a win for Bruce Rind.
What opening was played in Bruce Rind vs David Arnett?
The game opened with the Slav Defense: Exchange Variation, Symmetrical Line (ECO D14).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Bruce Rind vs David Arnett, or open it on the CipherChess analysis board to review it with the Stockfish engine.