Alfred Richters vs Alexander Boesel
2012 · Result 0–1 · Queen's Pawn Game: Zukertort Variation (D02).
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Game details
- White
- Alfred Richters (1919)
- Black
- Alexander Boesel (1992)
- Result
- 0–1
- Year
- 2012
- Opening
- Queen's Pawn Game: Zukertort Variation (D02)
About this chess game
This chess game between Alfred Richters (1919) and Alexander Boesel (1992) was played in 2012 and finished 0–1. The opening was the Queen's Pawn Game: Zukertort Variation (D02). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Alfred Richters games or Alexander Boesel games? This Alfred Richters vs Alexander Boesel encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Queen's Pawn Game: Zukertort Variation.
Frequently asked questions
Who won Alfred Richters vs Alexander Boesel?
Alfred Richters vs Alexander Boesel (2012) finished 0–1, a win for Alexander Boesel.
What opening was played in Alfred Richters vs Alexander Boesel?
The game opened with the Queen's Pawn Game: Zukertort Variation (ECO D02).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Alfred Richters vs Alexander Boesel, or open it on the CipherChess analysis board to review it with the Stockfish engine.