Roland Reuter vs Thomas Burger
2006 · Result 1–0 · English Opening: Symmetrical Variation, Normal Variation (A34).
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Game details
- White
- Roland Reuter (1978)
- Black
- Thomas Burger (1814)
- Result
- 1–0
- Year
- 2006
- Opening
- English Opening: Symmetrical Variation, Normal Variation (A34)
About this chess game
This chess game between Roland Reuter (1978) and Thomas Burger (1814) was played in 2006 and finished 1–0. The opening was the English Opening: Symmetrical Variation, Normal Variation (A34). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Roland Reuter games or Thomas Burger games? This Roland Reuter vs Thomas Burger encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the English Opening: Symmetrical Variation, Normal Variation.
Frequently asked questions
Who won Roland Reuter vs Thomas Burger?
Roland Reuter vs Thomas Burger (2006) finished 1–0, a win for Roland Reuter.
What opening was played in Roland Reuter vs Thomas Burger?
The game opened with the English Opening: Symmetrical Variation, Normal Variation (ECO A34).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Roland Reuter vs Thomas Burger, or open it on the CipherChess analysis board to review it with the Stockfish engine.