Sravan Renjith vs Daniel Howard Fernandez
Bob Wade 2026 | Bob Wade Masters, 2026 · Result 0–1 · Four Knights Game (C47).
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Game details
- White
- Sravan Renjith (2342)
- Black
- Daniel Howard Fernandez (2527)
- Result
- 0–1
- Event
- Bob Wade 2026 | Bob Wade Masters
- Year
- 2026
- Opening
- Four Knights Game (C47)
About this chess game
This chess game between Sravan Renjith (2342) and Daniel Howard Fernandez (2527) was played at Bob Wade 2026 | Bob Wade Masters in 2026 and finished 0–1. The opening was the Four Knights Game (C47). You can replay the full game move by move on the interactive board above, or open it on the CipherChess analysis board to study every move with the Stockfish engine.
Looking for more Sravan Renjith games or Daniel Howard Fernandez games? This Sravan Renjith vs Daniel Howard Fernandez encounter is one of millions of chess games indexed in the CipherChess mega database. Browse both players' full records, the openings they play most, and head-to-head results, then load any game onto the board to prepare your own lines against the Four Knights Game.
Frequently asked questions
Who won Sravan Renjith vs Daniel Howard Fernandez?
Sravan Renjith vs Daniel Howard Fernandez (2026) finished 0–1, a win for Daniel Howard Fernandez.
What opening was played in Sravan Renjith vs Daniel Howard Fernandez?
The game opened with the Four Knights Game (ECO C47).
Can I replay this chess game move by move?
Yes. Use the interactive board on this page to step through every move of Sravan Renjith vs Daniel Howard Fernandez, or open it on the CipherChess analysis board to review it with the Stockfish engine.